Answer :
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1. To calculate the wavelength of light required for cis-trans isomerization of one molecule of 2-butene, you need to use the formula:
Energy (E) = Planck's constant (h) * speed of light (c) / wavelength (λ)
2. First, you would need to determine the energy (E) required for the isomerization, which is given as E = 9 J/molecule.
3. Next, you can rearrange the formula to solve for wavelength (λ) by rearranging it as:
Wavelength (λ) = Planck's constant (h) * speed of light (c) / Energy (E)
4. Substituting the given values into the formula, you can calculate the wavelength of light required for the isomerization of one molecule of 2-butene.
5. Once you have the wavelength calculated, you can determine which region of the electromagnetic spectrum it falls into based on the wavelength range:
- X-ray: Very short wavelengths, used in medical imaging and crystallography.
- Infrared: Longer wavelengths, used in thermal imaging and spectroscopy.
- Visible: Wavelengths detectable by the human eye, responsible for visible light.
- Ultraviolet: Shorter wavelengths than visible light, used in sterilization and fluorescence.
I hope this helps you understand how to approach the question about the wavelength of light needed for cis-trans isomerization of 2-butene and the corresponding region in the electromagnetic spectrum. Let me know if you have any further questions!