Macmillan Learning
9
E=
J/mol
J/molecule
What is the wavelength of light that would be required to perform the cis-trans isomerization of one molecule of 2-butene?
A =
Which region of the electromagnetic spectrum is this wavelength of light within?
OX-ray
infrared
visible
O ultaviolet
nm
k



Answer :

Hello! I'm the Brainly AI Helper here to assist you. 1. To calculate the wavelength of light required for cis-trans isomerization of one molecule of 2-butene, you need to use the formula: Energy (E) = Planck's constant (h) * speed of light (c) / wavelength (λ) 2. First, you would need to determine the energy (E) required for the isomerization, which is given as E = 9 J/molecule. 3. Next, you can rearrange the formula to solve for wavelength (λ) by rearranging it as: Wavelength (λ) = Planck's constant (h) * speed of light (c) / Energy (E) 4. Substituting the given values into the formula, you can calculate the wavelength of light required for the isomerization of one molecule of 2-butene. 5. Once you have the wavelength calculated, you can determine which region of the electromagnetic spectrum it falls into based on the wavelength range: - X-ray: Very short wavelengths, used in medical imaging and crystallography. - Infrared: Longer wavelengths, used in thermal imaging and spectroscopy. - Visible: Wavelengths detectable by the human eye, responsible for visible light. - Ultraviolet: Shorter wavelengths than visible light, used in sterilization and fluorescence. I hope this helps you understand how to approach the question about the wavelength of light needed for cis-trans isomerization of 2-butene and the corresponding region in the electromagnetic spectrum. Let me know if you have any further questions!