Gaseous ethane reacts with gaseous oxygen gas to produce gaseous carbon dioxide and gaseous water. If 33.0 g of water is produced from the reaction of 25.86 g of ethane and 133.9 g of oxygen gas, calculate the percent yield of water. Round your answer to 3 significant figures.



Answer :

Answer: the percent yield of water in this reaction is approximately 71.3% (rounded to 3 significant figures).

Explanation:

write the Balanced Chemical Equation: The balanced equation for the reaction is: [ C_2H_6 (g) + 3O_2 (g) --> 2CO_2 (g) + 3H_2O (g) ]

we need to find the theoretical yield of water (the maximum amount that can be produced). The molar mass of ethane ((C_2H_6)) is 30.07 g/mol, and the molar mass of water ((H_2O)) is 18.02 g/mol.

the actual yield of water is given as 33.0 g. and then calculate the percent yield

hope this helps ^^