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What is the energy of a photon with a frequency of 3.6 × 1015 Hz? Planck’s constant is 6.63 × 10–34 J•s.

1.8 × 10–49 J
2.4 × 10–19 J
1.8 × 10–18 J
2.4 × 10–18 J



Answer :

Moalhazaa

Answer:

D. 2.4 ×10^-18 J

Explanation:

E = hf = 6.63×10^-34 × 3.6×10^15

E = 2.386×10^-18 J (approximately 2.4×10^-18 J).

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