Answer:
Volume of the cone = 1517.21 cubic units
Step-by-step explanation:
Using Pythagoras' Theorem,
[tex] {s}^{2} = {x}^{2} + {h}^{2} [/tex]
where h = vertical height of the cone.
[tex] {11}^{2} = {8}^{2} + {h}^{2} [/tex]
[tex] {h}^{2} = {11}^{2} - {8}^{2} = (11 - 8)(11 + 8)[/tex]
Applying difference of two squares
[tex] {h}^{2} = 3 \times 19 = 57[/tex]
h = √57
Volume of a cone = πr^2h = 3.14 × 8 × 8 × √ 57
= 200.86√57 = 1517.2147
Volume of the cone = 1517.21 cubic units
