Since the solution should be provided without reference to the Python code, let's proceed step-by-step:
**a. Draw and label the original rectangle with the measurements.**
Since I can't provide actual drawings here, I will describe how you would draw and label it:
1. Draw a rectangle on paper.
2. Label the longer side (length) as "2y + 4 cm."
3. Label the shorter side (width) as "y + 5 cm."
This is the original rectangle.
**b. Draw and label the enlarged rectangle with the measurements.**
For the enlarged rectangle:
1. Draw another rectangle, which should appear larger than the first one.
2. Label the longer side of this new rectangle as "5y + 8 cm."
3. Label the shorter side as "2y + 10 cm."
This represents the enlarged rectangle.
**c. With how much were the original rectangle enlarged?**
To find out how much the dimensions were increased, we need to compare the dimensions of the original rectangle with the dimensions of the enlarged rectangle:
Length increase:
The original length was "2y + 4 cm," and the enlarged length is "5y + 8 cm." To find the increase, we subtract the original length from the enlarged length: \( (5y + 8) - (2y + 4) \).
This simplifies to \( 3y + 4 \) cm, which means the length was increased by \( 3y \) plus 4 cm.
Width increase:
The original width was "y + 5 cm," and the enlarged width is "2y + 10 cm." To find the increase, subtract the original width from the enlarged width: \( (2y + 10) - (y + 5) \).
This simplifies to \( y + 5 \) cm, which means the width was increased by \( y \) plus 5 cm.
So, to fully answer part c, the original rectangle was enlarged in its length by \( 3y \) plus 4 cm and in its width by \( y \) plus 5 cm.
To answer whether the original and enlarged rectangles are similar, in geometrical terms, rectangles are similar if the ratios between corresponding lengths of both rectangles are equal. Since the ratios are different (2:5 for the length and 1:2 for the width), the rectangles would not be considered similar.
