Step-by-step explanation:
3x² - 16x - 12 = 0
for any quadratic equation
ax² + bx + c = 0
there is always the general solution
x = (-b ± sqrt(b² - 4ac))/(2a)
as an quadratic equation it has normally 2 solutions.
in our case
a = 3
b = -16
c = -12
x = (16 ± sqrt((-16)² - 4×3×-12))/(2×3) =
= (16 ± sqrt(256 + 144))/6 =
= (16 ± sqrt(400))/6 = (16 ± 20)/6
x1 = (16 + 20)/6 = 36/6 = 6
x2 = (16 - 20)/6 = -4/6 = -2/3
