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A gas cylinder contains 2 moles of helium gas at 20 °C. Assuming that helium behaves as an ideal gas, calculate the average kinetic energy per molecule. [Take = 1.38 × 10 - 23 / ]



Answer :

Answer:6.07 x 10^-21 J

Explanation:Substituting the given values into the formula, we get: Average kinetic energy = (3/2) (1.38 x 10^-23 J/K) (293.15 K) = 6.07 x 10^-21 J So, the average kinetic energy per molecule of the helium gas is approximately 6.1 x 10^-21 J. Answer Therefore, the correct answer is 6.1 × 10 − 21 J.

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