Answer :
Answer:
- 39
Explanation:
Let's assume the ten's place digit is 'x' and the unit's place digit is 'y'.
According to the problem, the ten's place digit is 6 less than the unit's place digit, so we can write the equation as:x = y - 6 ---(1)
The product of the digits is 27, so we can write the equation as:
- x * y = 27 ---(2)
Now, substitute the value of x from equation (1) into equation (2):
- (y - 6) * y = 27
Expanding the equation:
- y^2 - 6y = 27
Rearranging the equation:
- y^2 - 6y - 27 = 0
Now, let's solve this quadratic equation by factoring or using the quadratic formula.
Factoring the equation:
- (y - 9)(y + 3) = 0
Setting each factor to zero:
- y - 9 = 0 or y + 3 = 0
Solving for y:
y = 9 or y = -3
Since we are looking for a two-digit natural number, we discard the negative value.
- So, y = 9.
Now, substitute the value of y into equation (1) to find x:
- x = y - 6
- x = 9 - 6
- x = 3
Therefore, the number is 39.
So, the two-digit natural number is 39.
- Q.E. :))
If u have questions feel free to ask
