Answer:
-4/9
Step-by-step explanation:
To solve, rely on these rules
[tex]\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}[/tex]
[tex]\sqrt[3]{x} = x^{1\over3}[/tex]
[tex]\frac{1}{x^n} = x^{-n}[/tex]
Then the equation can be rewritten as:
[tex]\sqrt[3]{125} \cdot \sqrt[3]{x^2} \cdot \sqrt[3]{y^4} \cdot 5^{-1} \cdot x^{-2} \cdot y^{-1}[/tex]
simplifying to:
[tex]x^{2\over3} \cdot y^{4\over3} \cdot x^{-2} \cdot y^{-1}[/tex]
Then you can easily see that:
a = 1
b = -4/3
c = 1/3
So abc = -4/9
