Answer:
tan J = 4/3
Step-by-step explanation:
Using Pythagoras' Theorem,
[tex] {20}^{2} = {16}^{2} + {adjacent}^{2} [/tex]
[tex] {adjacent}^{2} = (20 - 16)(20 + 16) = 4 \times 36 = 144[/tex]
Take square roots of both sides
Adjacent = √144 = 12
Using Trigonometric ratio,
tan J = opposite/adjacent
tan J = 16/12 = 4/3
tan J = 4/3
