To determine the number of ways the 3 boys can sit in a row, you can use the concept of permutations. In permutations, the number of ways to arrange a set of objects is given by n!, where n is the number of objects.
1. Since there are 3 boys, the number of ways they can sit in a row is 3! = 3 x 2 x 1 = 6 ways.
2. Therefore, the correct answer is D. 20 is incorrect because it does not match the calculation of 3!.
So, the 3 boys can sit in a row in 6 different ways.
