5.
The frame for a wall is 2.4 m high and 4 m long. A diagonal brace must be added.
How long will it be correct to one decimal place?
Working out:
Answer:



Answer :

To solve this problem, we can use the Pythagorean theorem, which relates the sides of a right-angled triangle. The frame for the wall with a diagonal brace forms such a triangle, where the height and length of the frame are the perpendicular sides, and the diagonal brace will be the hypotenuse. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b): c² = a² + b² Here: - The height of the frame is "a", which equals 2.4 m. - The length of the frame is "b", which equals 4 m. - The diagonal brace is "c", which we are trying to find. Substitute the known values into the theorem: c² = (2.4)² + (4)² c² = 5.76 + 16 c² = 21.76 Now take the square root of both sides to find the length of the diagonal brace, "c": c = √21.76 To calculate the square root of 21.76: c ≈ 4.663 (using a calculator for accuracy) Now round the result to one decimal place: c ≈ 4.7 m Working out: The length of the diagonal brace to the nearest tenth is 4.7 meters. Answer: 4.7 m