A stack of playing cards contains 4 jacks, 5 queens, 3 kings, and 3 aces. Two cards will be randomly selected from the stack. What is the probability that a queen is chosen and replaced and then a queen is chosen again?



Answer :

Answer:

1/9

Step-by-step explanation:

There are a total of 4 + 5 + 3 + 3 = 15 cards in the stack.

The probability of selecting a queen on the first draw is:

P(First Queen)  = Number of queens / Total number of cards

= 5/ 15

= 1/3

Since the first queen is replaced, the total number of cards remains the same at 15 as do the total number of queens

The probability of selecting a queen on the second draw is also the same as the probability of selecting a queen on the first draw

P(second Queen) = 5/15 = 1/3

Since the two events are independent, the combined probability of selecting two queens on two draws after replacement is the product of the two probabilities:

P(2 queens with replacement) = P(first queen) * P(second queen)

= 1/3 * 1/3

= 1/9