Answer:
B.
[tex]y = \frac{5}{2}sin( \frac{2x}{3}) [/tex]
Step-by-step explanation:
Compare this with y = Asin(kx), where
A = amplitude (the highest vertical displacement of the wave particles) = 5/2
k = wave constant = 2π/wavelength = 2π / 3π = 2/3.
Option B conforms perfectly well with this.
