Answer :
To find the maximum height of the projectile, we need to determine the vertex of the parabolic function represented by the equation H = -16t^2 + 15t + 12.
The vertex of a parabolic function in the form y = ax^2 + bx + c is given by the formula:
Given our equation H = -16t^2 + 15t + 12, we can identify a = -16 and b = 15.
Plugging these values into the formula, we find:
To find the maximum height, substitute this value back into the original equation:
Solving this equation will give us the maximum height of the projectile.Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
You can do this a couple ways
1. Take the derivative h'(t)=-32t+15
Find where h'(t) = 0 or DNE to find the critical point in this case the only one is 0.469. Since the first derivative is positive to the left and negative to the right it is a maximum. Plugging .469 back into the equation the max is 15.516
2. -b/2a gives the x value of the vertex for a second degree polynomial and you can plug that x value back into the original equation to find the max.
3. Just graph it!
