Let's tackle these problems step by step:
For Amy's Box:
6. What is asked in the problem?
- We are asked to find the volume of rice the box can contain.
7. What facts are given?
- The dimensions of the box are given: it is 25 cm long, 15 cm wide, and 20 cm high.
8. What operations will be used?
- Multiplication will be used to calculate the volume.
9. How is the solution done? (formula)
- The solution is done using the formula for the volume of a box: Volume = length × width × height.
10. What is the answer?
- Using the formula:
Volume = 25 cm (length) × 15 cm (width) × 20 cm (height)
Volume = 375 cm² × 20 cm
Volume = 7500 cm³ (cubic centimeters)
For the Cargo Container:
11. What is asked in the problem?
- We are asked to find the volume of the cargo container.
12. What facts are given?
- The dimensions of the cargo container are given: it is 34 m long, 5 m wide, and 6 m tall.
13. What operations will be used?
- Multiplication will be used to calculate the volume.
14. How is the solution done? (formula)
- The solution is done using the formula for the volume of a box, which is the same as for the previous problem: Volume = length × width × height.
15. What is the answer?
- Applying the formula:
Volume = 34 m (length) × 5 m (width) × 6 m (height)
Volume = 170 m² × 6 m
Volume = 1020 m³ (cubic meters)
For the Open Box Problem:
16-17. An open box is 10 cm long, 5 cm wide, and 2 cm high. What is its volume?
- The volume of the open box is also found using the formula for the volume of a box: Volume = length × width × height.
- So, the volume of the open box will be:
Volume = 10 cm (length) × 5 cm (width) × 2 cm (height)
Volume = 50 cm² × 2 cm
Volume = 100 cm³ (cubic centimeters)
In summary, Amy's box can contain 7500 cubic centimeters of rice, the cargo container has a volume of 1020 cubic meters, and the open box has a volume of 100 cubic centimeters.
