The question asks for the concentration of a diluted solution. To solve this, you can use the principle of conservation of mass where the amount of solute remains constant before and after the dilution. This concept is also known as the dilution equation, which can be expressed as:
C1 V1 = C2 V2
Where:
C1 = initial concentration of the solution (before dilution)
V1 = initial volume of the solution (before dilution)
C2 = final concentration of the solution (after dilution)
V2 = final volume of the solution (after dilution)
We are given the following values in this problem:
C1 = 7M (initial concentration of nitric acid)
V1 = 25.0 mL (initial volume of nitric acid)
V2 = 200 mL (final volume after dilution)
We are asked to find C2, the final concentration after dilution.
Now, let's plug the values into the formula and solve for C2:
7M 25.0 mL = C2 200 mL
Now, divide both sides by 200 mL to solve for C2:
(7M 25.0 mL) / 200 mL = C2
C2 = (175.0 MmL) / 200 mL
C2 = 0.875 M
This means that after diluting 25.0 mL of 7M nitric acid to 200 mL, the concentration of the new solution is 0.875 M.
The correct answer is B) 0.875.
