Answer:
x2−2x+? is (x−1)2−1(x−1)2−1.
Step-by-step explanation:
To complete the square for the quadratic expression x2−2x+?x2−2x+?, let's first focus on the x2x2 and xx terms.For the quadratic x2−2xx2−2x, we'll complete the square by adding and subtracting (−22)2=1(2−2)2=1 inside the parentheses. This ensures that we're not changing the value of the expression:x2−2x+1−1x2−2x+1−1Now, we can rewrite this as a perfect square trinomial plus a constant:(x−1)2−1(x−1)2−1So, the completed square form of x2−2x+?x2−2x+? is (x−1)2−1(x−1)2−1.
