Jim catches a fish 49 yards away from the shore.
Later, he helps row the boat closer to the shore.
Now he is 27 yards away from the shore.
How many yards closer to shore is Jim now than
when he caught the fish?
Part A Write an addition equation that shows the
problem.

Question

10-05-2024
Physics

Answered

Jim catches a fish 49 yards away from the shore.
Later, he helps row the boat closer to the shore.
Now he is 27 yards away from the shore.
How many yards closer to shore is Jim now than
when he caught the fish?
Part A Write an addition equation that shows the
problem.

Answer :

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johnlumbab268 johnlumbab268 · Answer 1 · 2024-05-10T01:30:49-04:00

johnlumbab268 johnlumbab268

10-05-2024

Answer:

The addition equation is:

49

−

=

27

49−x=27

Explanation:

The addition equation that shows the problem is:

49

−

=

27

49−x=27

Where:

49

49 yards is the initial distance from the shore when Jim caught the fish,

x represents the yards closer to the shore after Jim helps row the boat,

27

27 yards is the new distance from the shore after rowing closer.

Answer Link

Jim catches a fish 49 yards away from the shore. Later, he helps row the boat closer to the shore. Now he is 27 yards away from the shore. How many yards closer to shore is Jim now than when he caught the fish? Part A Write an addition equation that shows the problem.

Answer :

Other Questions

Jim catches a fish 49 yards away from the shore.
Later, he helps row the boat closer to the shore.
Now he is 27 yards away from the shore.
How many yards closer to shore is Jim now than
when he caught the fish?
Part A Write an addition equation that shows the
problem.