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A loop of wire enclosing an area of 0.08 m² has a magnetic field passing through its plane at
an angle to the plane. The component of the field perpendicular to the plane is 0.60 T, and the
component parallel to the plane is 0.72 T.
(a) What is the magnetic flux through the coil?



Answer :

durojaiyesamuel519

Answer:

To find the magnetic flux through the coil, you can use the formula:

Magnetic flux (Φ) = Magnetic field (B) * Area (A) * cos(θ)

Where:

- Magnetic field (B) = 0.6 T (perpendicular component)

- Area (A) = 0.08 m²

- θ is the angle between the magnetic field and the plane of the coil.

Given that only the perpendicular component is provided, and the angle is not specified, we'll assume that the angle θ is 90 degrees, making the cosine of 90 degrees equal to 0.

So, the magnetic flux (Φ) through the coil is:

Φ = 0.6 T * 0.08 m² * cos(90°)

Φ = 0.6 T * 0.08 m² * 0

Therefore, the magnetic flux through the coil is 0.

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