A coil of wire with 60 turns and a cross sectional area of 0.06 m² lies with its plane
perpendicular to a magnetic field of magnitude 2.4 T. The coil is rapidly removed from the
magnetic field in a time of 0.4 s.
(a) What is the initial magnetic flux through the coil?
(b) What is the average value of the voltage induced in the coil?



Answer :

Answer:

The average value of the voltage induced in the coil is \( 21.6 \, \text{V} \).

Explanation:

To solve this problem, we'll use Faraday's law of electromagnetic induction, which states that the induced electromotive force (emf) in a closed circuit is equal to the rate of change of magnetic flux through the circuit. The formula for Faraday's law is:

\[ \text{emf} = -\frac{d\Phi}{dt} \]

Where:

- \( \text{emf} \) is the induced electromotive force,

- \( \frac{d\Phi}{dt} \) is the rate of change of magnetic flux through the coil.

(a) To find the initial magnetic flux through the coil, we'll use the formula for magnetic flux:

\[ \Phi = B \cdot A \cdot N \]

Where:

- \( \Phi \) is the magnetic flux,

- \( B \) is the magnetic field strength (2.4 T),

- \( A \) is the cross-sectional area of the coil (0.06 m²),

- \( N \) is the number of turns in the coil (60 turns).

Substituting the given values:

\[ \Phi = (2.4 \, \text{T}) \times (0.06 \, \text{m²}) \times (60) \]

\[ \Phi = 8.64 \, \text{Wb} \]

So, the initial magnetic flux through the coil is \( 8.64 \, \text{Wb} \).

(b) Now, to find the average value of the voltage induced in the coil, we'll use Faraday's law:

\[ \text{emf} = -\frac{d\Phi}{dt} \]

Since the coil is rapidly removed from the magnetic field, we can assume a constant rate of change of magnetic flux. Therefore, the average value of the induced voltage is:

\[ \text{Average emf} = \frac{\Delta \Phi}{\Delta t} \]

Where \( \Delta \Phi \) is the change in magnetic flux and \( \Delta t \) is the change in time.

Given that the time \( \Delta t \) is 0.4 s, we can calculate \( \Delta \Phi \) as the difference between the initial and final magnetic flux:

\[ \Delta \Phi = \Phi_{\text{initial}} - \Phi_{\text{final}} \]

\[ \Delta \Phi = 8.64 \, \text{Wb} - 0 \, \text{Wb} \]

\[ \Delta \Phi = 8.64 \, \text{Wb} \]

Now, we can calculate the average emf:

\[ \text{Average emf} = \frac{8.64 \, \text{Wb}}{0.4 \, \text{s}} \]

\[ \text{Average emf} = 21.6 \, \text{V} \]

So, the average value of the voltage induced in the coil is \( 21.6 \, \text{V} \).