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A CD is spinning at a rate of 200rpm before it is turned off. The CD comes to rest in 2.4s. What is the magnitude of its angular acceleration as it slows to a stop?



Answer :

Answer:

Explanation:

200 r/min * 1 min / 60 s   /  2.4 s = 1.3889  r /s^2

1.3889 r/ s^2  * 2pi Radians / r = 8.73 Radians/ s^2

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