Answer :
Answer:
Explanation:
C = 550 - 220 = 330
10 g * 330 C * .90 J/(g C) = 2970 J
[tex]\large{\underline{\boxed{\mathfrak{Answer}}}}[/tex]
To calculate the heat needed to raise the temperature of the aluminum, we use the formula:
Q = mcΔT
Where:
- Q is the heat energy (in joules)
- m is the mass of the substance (in grams)
- c is the specific heat capacity (in joules per gram per degree Celsius)
- ΔT is the change in temperature (in degrees Celsius)
Given:
- m = 10.0 g
- c = 0.90 J/g°C
- ΔT = 550°C - 220°C = 330°C
Now, plug in the values:
[tex]\tt{Q = (10.0 \, \text{g}) \times (0.90 \, \text{J/g°C}) \times (330°C) }[/tex]
[tex]\tt{Q = 2970 \, \text{J} }[/tex]
So, 2970 joules of heat are needed to raise the temperature of 10.0 g of aluminum from 220°C to 550°C.