How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 220C to 550C, it the specific heat of aluminum is 0.90 j/goC?



Answer :

Answer:

Explanation:

C = 550 - 220 = 330

10 g  *  330 C   *  .90 J/(g C) = 2970 J

[tex]\large{\underline{\boxed{\mathfrak{Answer}}}}[/tex]

To calculate the heat needed to raise the temperature of the aluminum, we use the formula:

Q = mcΔT

Where:

- Q is the heat energy (in joules)

- m is the mass of the substance (in grams)

- c is the specific heat capacity (in joules per gram per degree Celsius)

- ΔT is the change in temperature (in degrees Celsius)

Given:

- m = 10.0 g

- c = 0.90 J/g°C

- ΔT = 550°C - 220°C = 330°C

Now, plug in the values:

[tex]\tt{Q = (10.0 \, \text{g}) \times (0.90 \, \text{J/g°C}) \times (330°C) }[/tex]

[tex]\tt{Q = 2970 \, \text{J} }[/tex]

So, 2970 joules of heat are needed to raise the temperature of 10.0 g of aluminum from 220°C to 550°C.