Examine the following half-reactions and select the strongest oxidizing agent among the substances. [PtCl4]2−(aq) 2e− ⇄ Pt(s) 4Cl−(aq) E° = 0.755 V RuO4(s) 8H (aq) 8e− ⇄ Ru(s) 4H2O(l) E° = 1.038 V FeO42−(aq) 8H (aq) 3e− ⇄ Fe3 (aq) 4H2O(l) E° = 2.07 V H4XeO6(aq) 2H (aq) 2e− ⇄ XeO3(aq) 3H2O(l) E° = 2.42 V Multiple Choice [PtCl4]2–(aq) Cl−(aq) H4XeO6(aq) RuO4(s) HFeO4− (aq)