Answer: 375.195 g/mol
Explanation:
The chemical compound [tex]Ba(MnO_4)_2[/tex] is also known as barium permanganate. This compound has a molar mass of 375.195 g/mol.
Let us look at how to find this molar mass. To do this, we need to find the molar masses of each element in the compound, multiply them by any applicable subscripts, and add them all together.
Given:
[tex]Ba(MnO_4)_2[/tex]
Rewrite to multiply by the subscript:
[tex]Ba+2*(MnO_4)[/tex]
Rewrite to multiply by the subscript:
[tex]Ba+2*(Mn+4*(O))[/tex]
The molar mass of barium (Ba) is 137.327 u, the molar mass of manganese (Mn) is 54.938044 u, and the molar mass of oxygen (O) is 15.999 u:
[tex]137.327+2*(54.938044+4*(15.999))[/tex]
Multiply by 4:
[tex]137.327+2*(54.938044+63.996)[/tex]
Add:
[tex]137.327+2*(118.934044)[/tex]
Multiply by 2:
[tex]137.327+237.868088[/tex]
Add:
[tex]375.195088[/tex]
Please note that depending on how you round and what values for masses you use, your answer may differ. For example, another molar mass for barium permanganate may be 375.21 g/mol.
