2076 Set C Q.No. 9b A remote sensing satellite of the earth
evolves in a circular orbit at a height of 250 km above the
earth's surface. What is the orbital speed and period of
evolution of the satellite?
[4]



Answer :

Final answer:

To find the orbital speed of a satellite in a circular orbit, use V = √(GM/r). For the orbital period, employ Kepler's third law equation T = 2π√(r³/GM).


Explanation:

Orbital Speed: To calculate the orbital speed of a satellite in a circular orbit, we use the formula V = √(GM/r), where V is the speed, G is the gravitational constant, M is the mass of the Earth, and r is the distance from the center of the Earth to the satellite. Plugging in the values, we can find the orbital speed.

Orbital Period: The orbital period can be calculated using Kepler's third law, T = 2π√(r³/GM), where T is the period, r is the distance from the satellite to the center of the Earth, and GM is the product of the gravitational constant and the Earth's mass. By substituting the values, we can determine the period of evolution of the satellite.


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