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The decomposition of baking soda is represented by the following thermochemical equation:
2 NaHCO3 (s) + 129 kJ →Na2CO3 (s) + H2O (l) + CO2 (g)

Calculate the amount of heat required to decompose 1.28 mol of baking soda (NaHCO3). Round to the nearest hundredth.



Answer :

lexie2fine

Answer:  82.24 kJ

Explanation:  

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Alright, to calculate the amount of heat required to decompose 1.28 mol of baking soda (NaHCO3) using the given thermochemical equation:

2 NaHCO3 (s) + 129 kJ → Na2CO3 (s) + H2O (l) + CO2 (g)

We can set up a proportion to find out how much heat is required for 1.28 mol of NaHCO3:

1.28 mol NaHCO3 / 2 mol NaHCO3 = x kJ / 129 kJ

Solving for x:

x = 1.28 mol * 129 kJ / 2 mol

x = 165.12 kJ / 2

x = 82.56 kJ

So, approximately 82.56 kJ of heat is required to decompose 1.28 mol of baking soda.

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