To determine how tall Dwayne "The Rock" Johnson is based on the 1:7 ratio and the height of his action figure, you can follow these steps:
### Step-by-Step Solution
1. Understand the Ratio:
- The toy company uses a ratio of 1:7, which means 1 inch on the action figure corresponds to 7 inches in real life.
2. Identify Given Value:
- The action figure is 11 inches tall.
3. Set Up the Proportion:
- Based on the 1:7 ratio, we can set up the following proportion:
[tex]\[
\frac{\text{Height of the toy}}{\text{Height of the real person}} = \frac{1}{7}
\][/tex]
- Let [tex]\( H \)[/tex] represent the height of the real person.
4. Plug in the Given Values:
- Since we know the height of the toy (11 inches), we substitute this value into the proportion:
[tex]\[
\frac{11 \text{ inches}}{H} = \frac{1}{7}
\][/tex]
5. Solve for [tex]\( H \)[/tex]:
- To isolate [tex]\( H \)[/tex], you need to cross-multiply the equation:
[tex]\[
11 \times 7 = H \times 1
\][/tex]
[tex]\[
77 = H
\][/tex]
6. Conclusion:
- The height of Dwayne "The Rock" Johnson would be 77 inches.
### Final Height
- To convert inches to feet, note that there are 12 inches in a foot:
[tex]\[
77 \text{ inches} = \frac{77}{12} \text{ feet}
\][/tex]
[tex]\[
77 \text{ inches} \approx 6 \text{ feet and } 5 \text{ inches}
\][/tex]
So, Dwayne "The Rock" Johnson would be approximately 6 feet and 5 inches tall if his action figure, which is based on a 1:7 ratio, is 11 inches tall.
