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Unit 4 Test
4.29.24
+ S
11.Chris is building a rectangular deck. The length is 5 feet longer than twice its
width.
a. Draw a picture of the deck with all of its sides labeled.
×2



Answer :

GinnyAnswer
Certainly! Let's solve this step-by-step to understand the problem completely.

### Step-by-Step Solution

1. Understanding the Problem:
- We have a rectangular deck.
- The length of the deck is 5 feet longer than twice its width.

2. Label the Dimensions:
- Let [tex]\( w \)[/tex] represent the width of the deck.
- According to the problem, the length ([tex]\( l \)[/tex]) is 5 feet longer than twice the width. Therefore, we can write:
[tex]\[ l = 2w + 5 \][/tex]

3. Drawing the Diagram:
- We can now draw a rectangle and label its sides based on the given information.

Here is a simple sketch:

```
l
______________
| |
w| | w
| |
______________
l

Where:
l (Length) = 2w + 5
w (Width) = w
```

This diagram illustrates:
- Both the longer sides of the rectangle labeled as [tex]\( l = 2w + 5 \)[/tex].
- Both the shorter sides of the rectangle labeled as [tex]\( w \)[/tex].

### Summary
The problem is solved as we have:
- Represented the width by [tex]\( w \)[/tex].
- Expressed the length in terms of the width as [tex]\( l = 2w + 5 \)[/tex].
- Labeled the sides of the rectangle accordingly in the drawn picture.

Feel free to ask if you have any further questions on this topic or any other!

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