brookedavis503 brookedavis503
  • 14-05-2024
  • Mathematics
Answered

how do i solve log2 4x = 5



Answer :

Ty4theacc
Ty4theacc Ty4theacc
  • 14-05-2024

Brainliest please


Answer:

x=8

Step-by-step explanation:

1. Exponentiate both sides:
log_2(4x)=5
Since the logarithm is base 2, it means:
2^5=4x
2. Evaluate the exponent:
2^5=4x
32=4x

3. Divide both sides by the same factor:

32=4x

32/4= 4x/4

​4. Simplify:

x=8

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