To find the distance covered by the habal-habal motor bicycle when it reaches Aling Tina's Bakery, we can use the equation of motion for constant acceleration, which relates distance, initial velocity, acceleration, and time:
\[d = v_i t + \frac{1}{2} a t^2\]
Where:
- \(d\) is the distance covered,
- \(v_i\) is the initial velocity (which is 0 since the motor bicycle starts from rest),
- \(a\) is the acceleration (5.5 m/s²),
- \(t\) is the time (15 seconds).
Given that the initial velocity (\(v_i\)) is 0, we can simplify the equation to:
\[d = \frac{1}{2} a t^2\]
Now, we can plug in the values:
\[d = \frac{1}{2} \times 5.5 \, \text{m/s}^2 \times (15 \, \text{s})^2\]
\[d = \frac{1}{2} \times 5.5 \, \text{m/s}^2 \times 225 \, \text{s}^2\]
\[d = \frac{1}{2} \times 5.5 \times 225 \, \text{m}\]
\[d = \frac{1}{2} \times 1237.5 \, \text{m}\]
\[d = 618.75 \, \text{m}\]
Therefore, the relative distance covered when the habal-habal motor bicycle reaches Aling Tina's Bakery is 618.75 meters.
