Answer:
Ca(CO₃) is the limiting reactant
Explanation:
To find out which reactant is limiting, we need to compare the moles of each reactant to the stoichiometry of the balanced equation.
[tex]\sf H_2(SO_4) + Ca(CO_3) \rightarrow Ca(SO_4) + H_2O + CO_2 [/tex]
According to the balanced equation, 1 mole of H₂SO₄ reacts with 1 mole of CaCO₃.
Molar mass of the reactants :
Let's calculate the Number of moles of each reactant. Number of moles can be calculated by dividing the given mass by the Molar mass.
[tex] {\sf{Moles \: of \: H_2(SO_4) }}= \dfrac{100}{98.09} \\ \\ \ \ \ \ \ \ \ \ \ \ \ \ = 1.02 \: \sf{ mol}[/tex]
[tex] {\sf{Moles \: of \: Ca(CO_3)}} = \dfrac{100}{100.09} \\ \\ \ \ \ \ \ \ = 1.00 \: \sf{ mol}[/tex]
Now we need to compare the mole ratio of H₂(SO₄) to Ca(CO₃) in the balanced equation, on comparing we get:
1.00 moles of Ca(CO₃) is less than that of 1.02 moles of H₂(SO₄). Hence, Ca(CO₃) is the limiting reactant in this reaction