__Al2(SO4)3(aq) + __KOH(aq) --> __Al(OH)3(s) + __K2SO4(aq)

Given 5.8 grams of Al2(SO4)3 and 13.3 g of KOH, how much excess reactant remains?

Round to the tenths and indicate the appropriate unit and the chemical.

**Hint: This is a limiting reactant problem, and you should first convert to an amount of any product to determine which reactant is limiting and then go from there.