Answer :

To find the activity of (C3H7)4N ion in the solution, we first need to calculate the total concentration of (C3H7)4N ion in the solution considering both (C3H7)4NBr and (C3H7)4NCl.

Given:

- Concentration of (C3H7)4NBr = 0.0050 M

- Concentration of (C3H7)4NCl = 0.0050 M

Since both compounds dissociate completely in solution, the concentration of (C3H7)4N ion will be the same for both.

Total concentration of (C3H7)4N ion = Concentration of (C3H7)4NBr + Concentration of (C3H7)4NCl

                                            = 0.0050 M + 0.0050 M

                                            = 0.0100 M

The activity of a species in solution can be approximated by its concentration when the solution is sufficiently dilute. Therefore, in this case, the activity of (C3H7)4N ion would be approximately 0.0100 M.Answer:

Explanation: