To find the activity of (C3H7)4N ion in the solution, we first need to calculate the total concentration of (C3H7)4N ion in the solution considering both (C3H7)4NBr and (C3H7)4NCl.
Given:
- Concentration of (C3H7)4NBr = 0.0050 M
- Concentration of (C3H7)4NCl = 0.0050 M
Since both compounds dissociate completely in solution, the concentration of (C3H7)4N ion will be the same for both.
Total concentration of (C3H7)4N ion = Concentration of (C3H7)4NBr + Concentration of (C3H7)4NCl
= 0.0050 M + 0.0050 M
= 0.0100 M
The activity of a species in solution can be approximated by its concentration when the solution is sufficiently dilute. Therefore, in this case, the activity of (C3H7)4N ion would be approximately 0.0100 M.Answer:
Explanation: