Answer :
To calculate the resistance of a light bulb, we will use Ohm's Law, which relates voltage (V), current (I), and resistance (R) in an electrical circuit. Ohm’s Law is stated as:
[tex]\[ V = I \times R \][/tex]
where:
- [tex]\( V \)[/tex] is the voltage measured in volts (V),
- [tex]\( I \)[/tex] is the current measured in amperes (A),
- [tex]\( R \)[/tex] is the resistance measured in ohms (Ω).
We need to solve for resistance ([tex]\( R \)[/tex]). By rearranging the formula, we get:
[tex]\[ R = \frac{V}{I} \][/tex]
Given the information:
- Voltage ([tex]\( V \)[/tex]) = 120 volts,
- Current ([tex]\( I \)[/tex]) = 0.5 amperes.
Now, substitute the given values into the equation:
[tex]\[ R = \frac{120 \text{ volts}}{0.5 \text{ amperes}} \][/tex]
Perform the division:
[tex]\[ R = \frac{120}{0.5} \][/tex]
[tex]\[ R = 240 \text{ ohms} \][/tex]
Therefore, the resistance of the light bulb is [tex]\( 240 \)[/tex] ohms.
[tex]\[ V = I \times R \][/tex]
where:
- [tex]\( V \)[/tex] is the voltage measured in volts (V),
- [tex]\( I \)[/tex] is the current measured in amperes (A),
- [tex]\( R \)[/tex] is the resistance measured in ohms (Ω).
We need to solve for resistance ([tex]\( R \)[/tex]). By rearranging the formula, we get:
[tex]\[ R = \frac{V}{I} \][/tex]
Given the information:
- Voltage ([tex]\( V \)[/tex]) = 120 volts,
- Current ([tex]\( I \)[/tex]) = 0.5 amperes.
Now, substitute the given values into the equation:
[tex]\[ R = \frac{120 \text{ volts}}{0.5 \text{ amperes}} \][/tex]
Perform the division:
[tex]\[ R = \frac{120}{0.5} \][/tex]
[tex]\[ R = 240 \text{ ohms} \][/tex]
Therefore, the resistance of the light bulb is [tex]\( 240 \)[/tex] ohms.
