Answer:
V≈ [tex]27m^{3}[/tex]
Step-by-step explanation:
Using Formulas
A=[tex]6a^{2}[/tex]
V=[tex]a^{3}[/tex]
We already know the area is 54 so we can plug it into the equation from there
V= [tex]\sqrt{6} \frac{A^{3/2} }{36} = \sqrt{6} \frac{54^{3/2} }{36}[/tex] ≈ [tex]27m^{3}[/tex]
