Answer:
[tex]v_f = 105\text{ m/s}[/tex]
[tex]d = 1720\text{ m}[/tex]
Step-by-step explanation:
To solve for the airplane's final velocity, we can use the kinematics equation:
[tex]v_f = v_it + at[/tex]
We are given the values:
- [tex]a = 3.20\text{ m/s}^2[/tex]
- [tex]t = 32.8\text{ s}[/tex]
We can assume that the airplane started from standstill:
Plugging these values into the kinematics equation, we get:
[tex]v_f = 0 + \left(3.20\text{ m/s}^2\right)\!(32.8\text{ s})[/tex]
[tex]\boxed{v_f = 105\text{ m/s}}[/tex]
Further Note
We can also solve for the distance the plane travels before lifting off using another kinematics equation:
[tex]d=v_it+\dfrac{1}{2}at^2[/tex]
↓ plugging in the known values
[tex]d=0+\dfrac{1}{2}\!\left(3.20\text{ m/s}^2\right)(32.8\text{ s})^2[/tex]
[tex]\boxed{d = 1720\text{ m}}[/tex]
