Answer :
To determine the electrical energy consumed by an appliance over a specified time, we can follow these steps:
1. Calculate the Power Consumption:
- Power ([tex]\(P\)[/tex]) can be calculated using the formula:
[tex]\[ P = V \times I \][/tex]
where:
- [tex]\(V\)[/tex] is the voltage (in volts, V)
- [tex]\(I\)[/tex] is the current (in amperes, A)
Given:
[tex]\[ V = 120 \text{ V} \][/tex]
[tex]\[ I = 2 \text{ A} \][/tex]
Therefore,
[tex]\[ P = 120 \text{ V} \times 2 \text{ A} = 240 \text{ W} \][/tex]
2. Convert Power to Kilowatts:
- 1 kilowatt (kW) is equal to 1000 watts (W). To convert the power from watts to kilowatts, we use:
[tex]\[ P_{\text{kW}} = \frac{P_{\text{W}}}{1000} \][/tex]
So,
[tex]\[ P_{\text{kW}} = \frac{240 \text{ W}}{1000} = 0.24 \text{ kW} \][/tex]
3. Calculate Energy Consumption:
- Energy ([tex]\(E\)[/tex]) can be calculated using the formula:
[tex]\[ E = P \times t \][/tex]
where:
- [tex]\(P\)[/tex] is the power (in kilowatts, kW)
- [tex]\(t\)[/tex] is the time (in hours, h)
Given:
[tex]\[ t = 4 \text{ h} \][/tex]
Therefore,
[tex]\[ E = 0.24 \text{ kW} \times 4 \text{ h} = 0.96 \text{ kWh} \][/tex]
So, the power company provides approximately 0.96 kilowatt-hours (kWh) of electrical energy for the appliance during the 4-hour period.
1. Calculate the Power Consumption:
- Power ([tex]\(P\)[/tex]) can be calculated using the formula:
[tex]\[ P = V \times I \][/tex]
where:
- [tex]\(V\)[/tex] is the voltage (in volts, V)
- [tex]\(I\)[/tex] is the current (in amperes, A)
Given:
[tex]\[ V = 120 \text{ V} \][/tex]
[tex]\[ I = 2 \text{ A} \][/tex]
Therefore,
[tex]\[ P = 120 \text{ V} \times 2 \text{ A} = 240 \text{ W} \][/tex]
2. Convert Power to Kilowatts:
- 1 kilowatt (kW) is equal to 1000 watts (W). To convert the power from watts to kilowatts, we use:
[tex]\[ P_{\text{kW}} = \frac{P_{\text{W}}}{1000} \][/tex]
So,
[tex]\[ P_{\text{kW}} = \frac{240 \text{ W}}{1000} = 0.24 \text{ kW} \][/tex]
3. Calculate Energy Consumption:
- Energy ([tex]\(E\)[/tex]) can be calculated using the formula:
[tex]\[ E = P \times t \][/tex]
where:
- [tex]\(P\)[/tex] is the power (in kilowatts, kW)
- [tex]\(t\)[/tex] is the time (in hours, h)
Given:
[tex]\[ t = 4 \text{ h} \][/tex]
Therefore,
[tex]\[ E = 0.24 \text{ kW} \times 4 \text{ h} = 0.96 \text{ kWh} \][/tex]
So, the power company provides approximately 0.96 kilowatt-hours (kWh) of electrical energy for the appliance during the 4-hour period.