Answer :
To determine the power present in a circuit that has a current of 5 amperes (A) and a resistor of 4 ohms (Ω), we can use the power formula for electrical circuits. The formula is:
[tex]\[ P = I^2 \times R \][/tex]
where:
- [tex]\( P \)[/tex] is the power in watts (W),
- [tex]\( I \)[/tex] is the current in amperes (A),
- [tex]\( R \)[/tex] is the resistance in ohms (Ω).
Let's break down the calculation step by step:
1. Identify the given values:
- Current ([tex]\( I \)[/tex]) = 5 A
- Resistance ([tex]\( R \)[/tex]) = 4 Ω
2. Square the current ([tex]\( I \)[/tex]):
[tex]\[ I^2 = (5 \, \text{A})^2 = 25 \, \text{A}^2 \][/tex]
3. Multiply the squared current by the resistance:
[tex]\[ P = I^2 \times R = 25 \, \text{A}^2 \times 4 \, \text{Ω} = 100 \, \text{W} \][/tex]
So, the power present in the circuit is:
[tex]\[ \boxed{100 \, \text{watts}} \][/tex]
[tex]\[ P = I^2 \times R \][/tex]
where:
- [tex]\( P \)[/tex] is the power in watts (W),
- [tex]\( I \)[/tex] is the current in amperes (A),
- [tex]\( R \)[/tex] is the resistance in ohms (Ω).
Let's break down the calculation step by step:
1. Identify the given values:
- Current ([tex]\( I \)[/tex]) = 5 A
- Resistance ([tex]\( R \)[/tex]) = 4 Ω
2. Square the current ([tex]\( I \)[/tex]):
[tex]\[ I^2 = (5 \, \text{A})^2 = 25 \, \text{A}^2 \][/tex]
3. Multiply the squared current by the resistance:
[tex]\[ P = I^2 \times R = 25 \, \text{A}^2 \times 4 \, \text{Ω} = 100 \, \text{W} \][/tex]
So, the power present in the circuit is:
[tex]\[ \boxed{100 \, \text{watts}} \][/tex]
