Answer: 0.14 N/C
Explanation:
The formula for the electric field is given by:
E = F/q, where:
- E is the electric field
- F is the net force
- q is the charge
According to Newton's second law, the net force is also given by the equation:
F = ma, where:
- m is the mass
- a is the acceleration
Therefore, E = ma/q.
We are given that the particle is an electron and its acceleration is 2.5 · 10¹⁰ m/s²:
- mass of an electron: m = 9.11 · 10⁻³¹ kg
- charge of an electron: q = -1.6 · 10⁻¹⁹ C
- a = 2.5 · 10¹⁰ m/s²
Let's plug these values into the formula E = ma/q:
E = (9.11 · 10⁻³¹)(2.5 · 10¹⁰ m/s²)/(-1.6 · 10⁻¹⁹)
E = -0.14 N/C
The magnitude of the electric field is 0.14 N/C.
