If ABCD is dilated by a factor of 1/2 the
coordinate of C' would be:
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Answer:
C' (1, 2 )
Step-by-step explanation:
Assuming the dilatation is centred at the origin, then multiply the x and y coordinates of C by the scale factor of [tex]\frac{1}{2}[/tex]
C ( 2, 4 ) → C' ( [tex]\frac{1}{2}[/tex] (2), [tex]\frac{1}{2}[/tex] (4) ) → C' (1, 2 )