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a cylindrical cup has a height of 10cm. it holds a maximum of 503 cm cubed. What is the diameter of the cup rounded to the nearest whole number



Answer :

chibabykalu16

Answer:

≈ 8 cm

Step-by-step explanation:

The fomula for the volume of a cylinder is

[tex] \sf V = πr^2h[/tex]

Where ;

  • V is the volume
  • π is a constant approximately equal to 3.14
  • r is the radius
  • h is the height.

Given:

  • Volume (V) is 503 cm^3
  • Height (h) is 10 cm

we can rearrange the formula to solve for the radius (r):

[tex] \sf r = \sqrt{ \frac{V} {(πh)}}[/tex]

Plugging in the values, we get:

[tex] \sf {r = \sqrt{ \frac{503}{3.14 x 10} }}\\

\sf r ≈ √(16.05) \\

\sf r ≈ 4 cm[/tex]

Now, the diameter (d) is twice the radius (r):

d = 2r

d = 2 x 4 cm

d = 8 cm

So, the diameter of the cup is approximately 8 cm, rounded to the nearest whole number.

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