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A balloon has an initial temperature of 300k with a volume of 2.5 liters. The temperature of the gas is increased to 350k. Assuming no change in pressure or the number of molecules inside the balloon, what is the new volume?



Answer :

Explanation:

using Charles law

[tex] \frac{v1}{t1} = \frac{v2}{t2 } [/tex]

[tex]v2 = \frac{2.5 \times 350}{300} [/tex]

[tex]v2 = 2.91l[/tex]

The new volume is 2.91L

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