Answer:
∠RQS = 24°, ∠SRT = 28°
Step-by-step explanation:
Recognize that since QS is a diameter, angle QRS is a right angle, so m∠QRS = 90°
Use the inscribed angle theorem to find m∠RQS. Since arc QR = 48°, m∠RQS = 48°/2 = 24°
Find m∠SRT by subtracting m∠QRT from 90° as QRS and QRT form a linear pair. m∠SRT = 90° - 62° = 28°
