number 29 please help!!!
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Answer:
[tex]\text{m}\angle\text{CDA}=108^\circ[/tex]
Step-by-step explanation:
[tex]\text{m}\angle\text{CDA}+\text{m}\angle\text{ABC}=180^\circ\ \ \ [\text{Opposite angles of cyclic quadrilateral are }[/tex]
[tex]\text{supplementary.]}[/tex]
[tex]\text{or, m}\angle\text{CDA}+72^\circ=180^\circ\\\text{or, m}\angle\text{CDA}=108^\circ[/tex]