Answer :

Step-by-step explanation:

the last division step must have given us

ax + b

- ax + 2a

-----------------------

0 + b-2a = -132

b = 2a - 132

as we can see, we have 2 variables with only one equation. so, there are infinitely many functions that have a remainder of -132 when divided by (x + 2).

but as special case we can assume b = 0, and then

0 = 2a - 132

132 = 2a

a = 66

so, the function could look like

f(x) = ... + 66x

and then a division by (x + 2) would have a result of 66 and a remainder of -132.

but as I said this is only one of infinitely many possibilities.

e.g.

f(x) = ... + 64x - 4

the division by (x + 2) would have a result of 64 and a remainder of -132 (2a = 2×64 = 128, b = -4).