obtain the five-number summary for the given data.

Here are the average mathematics achievement scores for the ninth graders in 32 counties.

601 585 574 572 569 565 564 559 537 534 531 528 525 524 519 508 496 480 478 475 471 465 458 443 427 410 409 389 380 382 355 323



Answer :

Answer:

The is below

Step-by-step explanation:

To obtain the five-number summary, we need to find the minimum, maximum, median, and quartiles of the data set.

1. **Minimum**: The smallest value in the dataset is 323.

2. **Maximum**: The largest value in the dataset is 601.

3. **Median (Q2)**: To find the median, first arrange the data in ascending order:

323, 355, 380, 382, 389,

409,410 ,427 ,443 ,458 ,

465 ,471 ,475 ,478 ,480 ,

496 ,508 ,519

524525528531534537559565569574572585601

The middle value(s) are between positions (16 +1)/2 =8.5 and (17+1)/2=9

So Q2=(524+525)/2=524.5

4. **First Quartile (Q1)**: This is also known as lower quartile and represents the median of values below Q2.

For finding Q1:

Arrange all numbers from lowest to highest;

Find Median for Lower Half(Quartile)

In this case it will be average of position ((n/4)+((n/4)+1))/2 where n=32

So,Q1=((8+9)/2)=8.5

Therefore,Q1=(482+483)/2=482

5. **Third Quartile (Q3)**: This is also known as upper quartile and represents the median of values above Q3.

For finding Q3:

Arrange all numbers from lowest to highest;

Find Median for Upper Half(Quartile)

In this case it will be average of position (((n*3)/4)+(((n*3)/4)+1))/where n=32

So,Q3=((24+25))/24-25/26-27))=

Therefore,Q3=(558+559)/(26-27)=558

Therefore,the five-number summary for given data set would be:

Minimum:323

First Quartile(Q1):482

Median(Q2):524.5

Third Quartile(Q3):558

Maximum:601