Finding the bond energy of H₆ requires some knowledge of chemistry and a bit of math.
H₆ is not a stable molecule, as it is not possible to form a molecule with six hydrogen atoms. The highest possible hydrogen compound is H₂O (water), which has two hydrogen atoms.
However, if you're asking about the bond energy of H-H in H₂ (as you mentioned), it's indeed around 436 kJ/mol.
If you're asking about the bond energy of H-H in H₂O, it's slightly lower due to the presence of the oxygen atom. The bond energy of H-H in H₂O is approximately 365 kJ/mol.
To calculate the bond energy of H-H in H₂O, you can use the following formula:
Bond energy (H-H) = Bond energy (H₂O) - Bond energy (H-O)
where Bond energy (H-O) is the bond energy of the hydrogen-oxygen bond in H₂O.
The bond energy of H-O in H₂O is around 463 kJ/mol. So, using the formula:
Bond energy (H-H) = 463 kJ/mol - 436 kJ/mol ≈ 27 kJ/mol
So, the bond energy of H-H in H₂O is approximately 27 kJ/mol.
Please note that these values are approximate and may vary depending on the source and method used to calculate the bond energies.
