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The difference between Jon’s age and Sue’s age is 18 years. If Jon is six years more than five times Sue’s age, how old is each person from least to greatest. (TYPE YOUR ANSWER WITH COMMAS, NO SPACES, NO SYMBOLS, NO "AND" -> Ex: 1,2,3)



Answer :

Answer:

Sue is 3, Jon is 21

Step-by-step explanation:

We can first represent this as an algebraic equation. J=Jon, and Sue=S.

Since the difference is 18 years, J-S= 18. Jon is six years more than five times Sue’s age. While that may sound tricky, just start from the beginning. Six more, there is a 6 plus somewhere. 5 times sue’s age, so we have to multiply S by 5. In the end:

J=5S+6

: represents the relationship

We also have the equation,

J-S=18

We can substitute 5x+6 for J in the second equation:

5S+6-S=18. After simplifying, we see that 4S=12

So, Sue is 3 years old.

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