. A vertical parabola opens upward, has its vertex in the fourth quadrant, and its equation is y
2 + bx + c. Are the coefficients a, b, and c positive or negative? Find all possible ca
and sketch the graph for each case.



Answer :

To determine the signs of the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex], and to analyze the equation [tex]\( y = ax^2 + bx + c \)[/tex], let's break down the question step by step.

### Step 1: Understanding the Basic Properties

1. The parabola opens upward.
2. The vertex is in the fourth quadrant.

Properties of the Parabola Equation:
The general form of a parabolic equation is [tex]\( y = ax^2 + bx + c \)[/tex]:

- [tex]\( a \)[/tex]: Determines the direction of the parabola. If [tex]\( a > 0 \)[/tex], the parabola opens upward. If [tex]\( a < 0 \)[/tex], the parabola opens downward.
- [tex]\( b \)[/tex]: Affects the symmetry and tilt of the parabola.
- [tex]\( c \)[/tex]: Represents the y-intercept, i.e., the value of [tex]\( y \)[/tex] when [tex]\( x = 0 \)[/tex].

### Step 2: Analyzing the Direction and Location of the Vertex

#### Coefficient [tex]\( a \)[/tex]:

Since the parabola opens upward, [tex]\( a \)[/tex] must be positive.

[tex]\[ a > 0 \][/tex]

#### Vertex in the Fourth Quadrant:

The coordinates of the vertex [tex]\((h, k)\)[/tex] are in the fourth quadrant, meaning [tex]\( h > 0 \)[/tex] and [tex]\( k < 0 \)[/tex].

The x-coordinate of the vertex [tex]\( h \)[/tex] is given by the formula:

[tex]\[ h = -\frac{b}{2a} \][/tex]

Since [tex]\( h > 0 \)[/tex], it follows that:

[tex]\[ -\frac{b}{2a} > 0 \][/tex]

Given [tex]\( a > 0 \)[/tex], to satisfy this inequality, [tex]\( b \)[/tex] must be less than 0.

[tex]\[ b < 0 \][/tex]

#### Coefficient [tex]\( c \)[/tex]:

The fourth quadrant means the vertex is below the x-axis, indicating that:

[tex]\[ k < 0 \][/tex]

The vertex [tex]\( k \)[/tex] of the parabola is calculated with the formula:

[tex]\[ k = c - \frac{b^2}{4a} \][/tex]

Since [tex]\( k < 0 \)[/tex], and knowing that [tex]\( a > 0 \)[/tex] and [tex]\( b < 0 \)[/tex]:

[tex]\[ c - \frac{b^2}{4a} < 0 \][/tex]

To satisfy this innquality, [tex]\( c \)[/tex] has to be smaller than [tex]\( \frac{b^2}{4a} \)[/tex].

### Step 3: Summarizing the Coefficients

- [tex]\( a > 0 \)[/tex]: Positive, since the parabola opens upwards.
- [tex]\( b < 0 \)[/tex]: Negative, based on the direction of the vertex.
- [tex]\( c \)[/tex]: Depends on the equation [tex]\( c < \frac{b^2}{4a}\)[/tex] might be positive or negative.

### Step 4: Possible Graphs:

1. Case 1: [tex]\( c \)[/tex] is positive.
- This means the y-intercept is above the x-axis, while the vertex is below it and the parabola eventually moves upwards past the x-axis.

2. Case 2: [tex]\( c \)[/tex] is negative.
- This means the y-intercept is below the x-axis, and the vertex is also in the fourth quadrant.

### Example Equations and Sketches:

#### Case 1: [tex]\( c \)[/tex] Positive
Example Equation:
[tex]\[ y = 2x^2 - 4x + 1 \][/tex]

#### Case 2: [tex]\( c \)[/tex] Negative
Example Equation:
[tex]\[ y = 2x^2 - 4x - 5 \][/tex]

### Sketches:

For each sketch, focus on:
- The vertex must be in the fourth quadrant.
- The parabola must open upwards.
- In the first case, the y-intercept is above the x-axis.
- In the second case, the y-intercept is below the x-axis.

This analysis gives a comprehensive view of how the coefficients affect the graph and helps understand the nature of the quadratic equation based on given conditions.